Tuesday, July 04, 2006

XSLT Replace Template

I was working on a site today that required me to split a string in the form of a=1;b=2;c=3 in xsl. Now xsl does provide a translate() function but it doesn't traverse the whole string doing a normal replacement as you might expect. Instead a trawled the internet and found the following little template which nicely recurses through and does the replacement. I thought I'd post it here so I can find it again - and share it with the world of course!
 

  <xsl:template name="replace">

    <xsl:param name="string" select="." />

    <xsl:choose>

      <xsl:when test="not($string)" />

      <xsl:when test="contains($string, ';')">

        <xsl:value-of select="substring-before($string, ';')" />

        <br />

        <xsl:call-template name="replace">

          <xsl:with-param name="string" select="substring-after($string, ';')" />

        </xsl:call-template>

      </xsl:when>

      <xsl:otherwise>

        <xsl:value-of select="$string" />

        <br />

      </xsl:otherwise>

    </xsl:choose>

  </xsl:template>

 

All you need do is call the template and pass your input into with $string param, in my case this was the ";". Then replace the <br/> tags with whatever you need to replace your input string with - easy!

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